3I2x+6I=-12

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Solution for 3I2x+6I=-12 equation:



32I+6=-12
We move all terms to the left:
32I+6-(-12)=0
We add all the numbers together, and all the variables
32I+18=0
We move all terms containing I to the left, all other terms to the right
32I=-18
I=-18/32
I=-9/16

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