3R-30=-2(r-10)-35

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Solution for 3R-30=-2(r-10)-35 equation: 



3-30=-2(R-10)-35

We move all terms to the left:

3-30-(-2(R-10)-35)=0

We add all the numbers together, and all the variables

-(-2(R-10)-35)-27=0



We calculate terms in parentheses: -(-2(R-10)-35), so:

-2(R-10)-35

We multiply parentheses

-2R+20-35

We add all the numbers together, and all the variables

-2R-15

Back to the equation:

-(-2R-15)



We get rid of parentheses

2R+15-27=0

We add all the numbers together, and all the variables

2R-12=0

We move all terms containing R to the left, all other terms to the right

2R=12

R=12/2

R=6

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