3X(2x-2)=2X(3x+9)

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Solution for 3X(2x-2)=2X(3x+9) equation: 



3X(2X-2)=2X(3X+9)

We move all terms to the left:

3X(2X-2)-(2X(3X+9))=0

We multiply parentheses

6X^2-6X-(2X(3X+9))=0



We calculate terms in parentheses: -(2X(3X+9)), so:

2X(3X+9)

We multiply parentheses

6X^2+18X

Back to the equation:

-(6X^2+18X)



We get rid of parentheses

6X^2-6X^2-6X-18X=0

We add all the numbers together, and all the variables

-24X=0

X=0/-24

X=0

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