3X+1=2-(Z-4)+3z

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Solution for 3X+1=2-(Z-4)+3z equation: 



3X+1=2-(-4)+3X

We move all terms to the left:

3X+1-(2-(-4)+3X)=0



We calculate terms in parentheses: -(2-(-4)+3X), so:

2-(-4)+3X

determiningTheFunctionDomain
3X+2-(-4)

We add all the numbers together, and all the variables

3X+6

Back to the equation:

-(3X+6)



We get rid of parentheses

3X-3X-6+1=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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