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3X+3=1/2X+13
We move all terms to the left:
3X+3-(1/2X+13)=0
Domain of the equation: 2X+13)!=0We get rid of parentheses
X∈R
3X-1/2X-13+3=0
We multiply all the terms by the denominator
3X*2X-13*2X+3*2X-1=0
Wy multiply elements
6X^2-26X+6X-1=0
We add all the numbers together, and all the variables
6X^2-20X-1=0
a = 6; b = -20; c = -1;
Δ = b2-4ac
Δ = -202-4·6·(-1)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{106}}{2*6}=\frac{20-2\sqrt{106}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{106}}{2*6}=\frac{20+2\sqrt{106}}{12} $
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