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3X+X2=53
We move all terms to the left:
3X+X2-(53)=0
We add all the numbers together, and all the variables
X^2+3X-53=0
a = 1; b = 3; c = -53;
Δ = b2-4ac
Δ = 32-4·1·(-53)
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{221}}{2*1}=\frac{-3-\sqrt{221}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{221}}{2*1}=\frac{-3+\sqrt{221}}{2} $
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