3X2+-48x=0

Solution for 3X2+-48x=0 equation:

3X^2+-48X=0

We add all the numbers together, and all the variables

3X^2-48X=0

a = 3; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·3·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*3}=\frac{0}{6}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*3}=\frac{96}{6}
=16
$