3X2-3x-4=0

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Solution for 3X2-3x-4=0 equation: 



3X^2-3X-4=0

a = 3; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·3·(-4)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*3}=\frac{3-\sqrt{57}}{6}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*3}=\frac{3+\sqrt{57}}{6}
$

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