3Y/2Y-2-2,5Y/5Y-5

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Solution for 3Y/2Y-2-2,5Y/5Y-5 equation: 


Y in (-oo:+oo)

((3*Y)/2)*Y-(((2.5*Y)/5)*Y)-5-2 = 0

((3*Y)/2)*Y-0.5*Y^2-5-2 = 0

1*Y^2 = 7 // : 1

Y^2 = 7

Y^2 = 7 // ^ 1/2

abs(Y) = 7^(1/2)

Y = 7^(1/2) or Y = -7^(1/2)

Y in { 7^(1/2), -7^(1/2) }

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