3a(4+a)=3a(4+a)

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Solution for 3a(4+a)=3a(4+a) equation: 



3a(4+a)=3a(4+a)

We move all terms to the left:

3a(4+a)-(3a(4+a))=0

We add all the numbers together, and all the variables

3a(a+4)-(3a(a+4))=0

We multiply parentheses

3a^2+12a-(3a(a+4))=0



We calculate terms in parentheses: -(3a(a+4)), so:

3a(a+4)

We multiply parentheses

3a^2+12a

Back to the equation:

-(3a^2+12a)



We get rid of parentheses

3a^2-3a^2+12a-12a=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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