3a(4+a)=3a(4+a)

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Solution for 3a(4+a)=3a(4+a) equation:



3a(4+a)=3a(4+a)
We move all terms to the left:
3a(4+a)-(3a(4+a))=0
We add all the numbers together, and all the variables
3a(a+4)-(3a(a+4))=0
We multiply parentheses
3a^2+12a-(3a(a+4))=0
We calculate terms in parentheses: -(3a(a+4)), so:
3a(a+4)
We multiply parentheses
3a^2+12a
Back to the equation:
-(3a^2+12a)
We get rid of parentheses
3a^2-3a^2+12a-12a=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0

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