3a(4a-5)-30=4a(3a+1)+8

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Solution for 3a(4a-5)-30=4a(3a+1)+8 equation: 



3a(4a-5)-30=4a(3a+1)+8

We move all terms to the left:

3a(4a-5)-30-(4a(3a+1)+8)=0

We multiply parentheses

12a^2-15a-(4a(3a+1)+8)-30=0



We calculate terms in parentheses: -(4a(3a+1)+8), so:

4a(3a+1)+8

We multiply parentheses

12a^2+4a+8

Back to the equation:

-(12a^2+4a+8)



We get rid of parentheses

12a^2-12a^2-15a-4a-8-30=0

We add all the numbers together, and all the variables

-19a-38=0

We move all terms containing a to the left, all other terms to the right

-19a=38

a=38/-19

a=-2

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