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3a(a+-5)=30
We move all terms to the left:
3a(a+-5)-(30)=0
We add all the numbers together, and all the variables
3a(a-5)-30=0
We multiply parentheses
3a^2-15a-30=0
a = 3; b = -15; c = -30;
Δ = b2-4ac
Δ = -152-4·3·(-30)
Δ = 585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{585}=\sqrt{9*65}=\sqrt{9}*\sqrt{65}=3\sqrt{65}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3\sqrt{65}}{2*3}=\frac{15-3\sqrt{65}}{6} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3\sqrt{65}}{2*3}=\frac{15+3\sqrt{65}}{6} $
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