3a(a+-5)=30

Solution for 3a(a+-5)=30 equation:

3a(a+-5)=30

We move all terms to the left:

3a(a+-5)-(30)=0

We add all the numbers together, and all the variables

3a(a-5)-30=0

We multiply parentheses

3a^2-15a-30=0

a = 3; b = -15; c = -30;
Δ = b2-4ac
Δ = -152-4·3·(-30)
Δ = 585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{585}=\sqrt{9*65}=\sqrt{9}*\sqrt{65}=3\sqrt{65}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3\sqrt{65}}{2*3}=\frac{15-3\sqrt{65}}{6}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3\sqrt{65}}{2*3}=\frac{15+3\sqrt{65}}{6}
$