3a(b+c)+2b(a+c)-c(2a+3b)=

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Solution for 3a(b+c)+2b(a+c)-c(2a+3b)= equation:


Simplifying
3a(b + c) + 2b(a + c) + -1c(2a + 3b) = 0
(b * 3a + c * 3a) + 2b(a + c) + -1c(2a + 3b) = 0
(3ab + 3ac) + 2b(a + c) + -1c(2a + 3b) = 0
3ab + 3ac + (a * 2b + c * 2b) + -1c(2a + 3b) = 0
3ab + 3ac + (2ab + 2bc) + -1c(2a + 3b) = 0
3ab + 3ac + 2ab + 2bc + (2a * -1c + 3b * -1c) = 0
3ab + 3ac + 2ab + 2bc + (-2ac + -3bc) = 0

Reorder the terms:
3ab + 2ab + 3ac + -2ac + 2bc + -3bc = 0

Combine like terms: 3ab + 2ab = 5ab
5ab + 3ac + -2ac + 2bc + -3bc = 0

Combine like terms: 3ac + -2ac = 1ac
5ab + 1ac + 2bc + -3bc = 0

Combine like terms: 2bc + -3bc = -1bc
5ab + 1ac + -1bc = 0

Solving
5ab + 1ac + -1bc = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'bc' to each side of the equation.
5ab + 1ac + -1bc + bc = 0 + bc

Combine like terms: -1bc + bc = 0
5ab + 1ac + 0 = 0 + bc
5ab + 1ac = 0 + bc
Remove the zero:
5ab + 1ac = bc

Combine like terms: bc + -1bc = 0
5ab + 1ac + -1bc = 0

The solution to this equation could not be determined.

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