3a+(2a-5)+2(a+2)=20

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Solution for 3a+(2a-5)+2(a+2)=20 equation: 



3a+(2a-5)+2(a+2)=20

We move all terms to the left:

3a+(2a-5)+2(a+2)-(20)=0

We multiply parentheses

3a+(2a-5)+2a+4-20=0

We get rid of parentheses

3a+2a+2a-5+4-20=0

We add all the numbers together, and all the variables

7a-21=0

We move all terms containing a to the left, all other terms to the right

7a=21

a=21/7

a=3

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