3a+(2a-5)=13-2(a+20

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Solution for 3a+(2a-5)=13-2(a+20 equation: 



3a+(2a-5)=13-2(a+20

We move all terms to the left:

3a+(2a-5)-(13-2(a+20)=0

We get rid of parentheses

3a+2a-(13-2(a+20)-5=0

We add all the numbers together, and all the variables

5a-(13-2(a+20)-5=0

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