3a+(b+3)i=9+8i

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Solution for 3a+(b+3)i=9+8i equation:


Simplifying
3a + (b + 3) * i = 9 + 8i

Reorder the terms:
3a + (3 + b) * i = 9 + 8i

Reorder the terms for easier multiplication:
3a + i(3 + b) = 9 + 8i
3a + (3 * i + b * i) = 9 + 8i

Reorder the terms:
3a + (bi + 3i) = 9 + 8i
3a + (bi + 3i) = 9 + 8i

Solving
3a + bi + 3i = 9 + 8i

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1bi' to each side of the equation.
3a + bi + -1bi + 3i = 9 + -1bi + 8i

Combine like terms: bi + -1bi = 0
3a + 0 + 3i = 9 + -1bi + 8i
3a + 3i = 9 + -1bi + 8i

Add '-3i' to each side of the equation.
3a + 3i + -3i = 9 + -1bi + 8i + -3i

Combine like terms: 3i + -3i = 0
3a + 0 = 9 + -1bi + 8i + -3i
3a = 9 + -1bi + 8i + -3i

Combine like terms: 8i + -3i = 5i
3a = 9 + -1bi + 5i

Divide each side by '3'.
a = 3 + -0.3333333333bi + 1.666666667i

Simplifying
a = 3 + -0.3333333333bi + 1.666666667i

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