3a+1/3(6a-a)=1/2(10a-6)

Solution for 3a+1/3(6a-a)=1/2(10a-6) equation:

3a+1/3(6a-a)=1/2(10a-6)

We move all terms to the left:

3a+1/3(6a-a)-(1/2(10a-6))=0


Domain of the equation: 3(6a-a)!=0

a∈R



Domain of the equation: 2(10a-6))!=0

a∈R


We add all the numbers together, and all the variables

3a+1/3(+5a)-(1/2(10a-6))=0

We calculate fractions


3a+(2a1/(3(+5a)*2(10a-6)))+(-3a0/(3(+5a)*2(10a-6)))=0


We calculate terms in parentheses: +(2a1/(3(+5a)*2(10a-6))), so:

2a1/(3(+5a)*2(10a-6))

We multiply all the terms by the denominator


2a1

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)



We calculate terms in parentheses: +(-3a0/(3(+5a)*2(10a-6))), so:

-3a0/(3(+5a)*2(10a-6))

We multiply all the terms by the denominator


-3a0

We add all the numbers together, and all the variables

-3a

Back to the equation:

+(-3a)


We add all the numbers together, and all the variables

5a+(-3a)=0

We get rid of parentheses

5a-3a=0

We add all the numbers together, and all the variables

2a=0

a=0/2

a=0