3a+12=4a+12-a

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Solution for 3a+12=4a+12-a equation: 



3a+12=4a+12-a

We move all terms to the left:

3a+12-(4a+12-a)=0

We add all the numbers together, and all the variables

3a-(3a+12)+12=0

We get rid of parentheses

3a-3a-12+12=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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