3a+2(4a+2a)=105

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Solution for 3a+2(4a+2a)=105 equation: 



3a+2(4a+2a)=105

We move all terms to the left:

3a+2(4a+2a)-(105)=0

We add all the numbers together, and all the variables

3a+2(+6a)-105=0

We multiply parentheses

3a+12a-105=0

We add all the numbers together, and all the variables

15a-105=0

We move all terms containing a to the left, all other terms to the right

15a=105

a=105/15

a=7

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