3a+2(a+2)=20-(2a-5)

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Solution for 3a+2(a+2)=20-(2a-5) equation: 



3a+2(a+2)=20-(2a-5)

We move all terms to the left:

3a+2(a+2)-(20-(2a-5))=0

We multiply parentheses

3a+2a-(20-(2a-5))+4=0



We calculate terms in parentheses: -(20-(2a-5)), so:

20-(2a-5)

determiningTheFunctionDomain
-(2a-5)+20

We get rid of parentheses

-2a+5+20

We add all the numbers together, and all the variables

-2a+25

Back to the equation:

-(-2a+25)



We add all the numbers together, and all the variables

5a-(-2a+25)+4=0

We get rid of parentheses

5a+2a-25+4=0

We add all the numbers together, and all the variables

7a-21=0

We move all terms containing a to the left, all other terms to the right

7a=21

a=21/7

a=3

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