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3a+2/2a-4=0
Domain of the equation: 2a!=0We multiply all the terms by the denominator
a!=0/2
a!=0
a∈R
3a*2a-4*2a+2=0
Wy multiply elements
6a^2-8a+2=0
a = 6; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·6·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*6}=\frac{4}{12} =1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*6}=\frac{12}{12} =1 $
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