3a+2=(3a-6)/3

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Solution for 3a+2=(3a-6)/3 equation: 



3a+2=(3a-6)/3

We move all terms to the left:

3a+2-((3a-6)/3)=0

We multiply all the terms by the denominator


3a*3)-((3a-6)+2*3)=0

We add all the numbers together, and all the variables

3a*3)-((3a-6)=0

Wy multiply elements

9a^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{18}=0$

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