3a+2c=4(b+a)

Solution for 3a+2c=4(b+a) equation:

Simplifying
3a + 2c = 4(b + a)

Reorder the terms:
3a + 2c = 4(a + b)
3a + 2c = (a * 4 + b * 4)
3a + 2c = (4a + 4b)

Solving
3a + 2c = 4a + 4b

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4a' to each side of the equation.
3a + -4a + 2c = 4a + -4a + 4b

Combine like terms: 3a + -4a = -1a
-1a + 2c = 4a + -4a + 4b

Combine like terms: 4a + -4a = 0
-1a + 2c = 0 + 4b
-1a + 2c = 4b

Add '-2c' to each side of the equation.
-1a + 2c + -2c = 4b + -2c

Combine like terms: 2c + -2c = 0
-1a + 0 = 4b + -2c
-1a = 4b + -2c

Divide each side by '-1'.
a = -4b + 2c

Simplifying
a = -4b + 2c