3a+3(3a-4)=-48

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Solution for 3a+3(3a-4)=-48 equation: 



3a+3(3a-4)=-48

We move all terms to the left:

3a+3(3a-4)-(-48)=0

We add all the numbers together, and all the variables

3a+3(3a-4)+48=0

We multiply parentheses

3a+9a-12+48=0

We add all the numbers together, and all the variables

12a+36=0

We move all terms containing a to the left, all other terms to the right

12a=-36

a=-36/12

a=-3

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