3a+3a+3a=2(a+3+a+7)

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Solution for 3a+3a+3a=2(a+3+a+7) equation: 



3a+3a+3a=2(a+3+a+7)

We move all terms to the left:

3a+3a+3a-(2(a+3+a+7))=0

We add all the numbers together, and all the variables

3a+3a+3a-(2(2a+10))=0

We add all the numbers together, and all the variables

9a-(2(2a+10))=0



We calculate terms in parentheses: -(2(2a+10)), so:

2(2a+10)

We multiply parentheses

4a+20

Back to the equation:

-(4a+20)



We get rid of parentheses

9a-4a-20=0

We add all the numbers together, and all the variables

5a-20=0

We move all terms containing a to the left, all other terms to the right

5a=20

a=20/5

a=4

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