3a+4(2a-5)-(6a-9-3)=12

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Solution for 3a+4(2a-5)-(6a-9-3)=12 equation: 



3a+4(2a-5)-(6a-9-3)=12

We move all terms to the left:

3a+4(2a-5)-(6a-9-3)-(12)=0

We add all the numbers together, and all the variables

3a+4(2a-5)-(6a-12)-12=0

We multiply parentheses

3a+8a-(6a-12)-20-12=0

We get rid of parentheses

3a+8a-6a+12-20-12=0

We add all the numbers together, and all the variables

5a-20=0

We move all terms containing a to the left, all other terms to the right

5a=20

a=20/5

a=4

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