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3a+4(5-2a)-12=2(4-5a)
We move all terms to the left:
3a+4(5-2a)-12-(2(4-5a))=0
We add all the numbers together, and all the variables
3a+4(-2a+5)-(2(-5a+4))-12=0
We multiply parentheses
3a-8a-(2(-5a+4))+20-12=0
We calculate terms in parentheses: -(2(-5a+4)), so:We add all the numbers together, and all the variables
2(-5a+4)
We multiply parentheses
-10a+8
Back to the equation:
-(-10a+8)
-5a-(-10a+8)+8=0
We get rid of parentheses
-5a+10a-8+8=0
We add all the numbers together, and all the variables
5a=0
a=0/5
a=0
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