3a+4(a-10)=a+20

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Solution for 3a+4(a-10)=a+20 equation: 



3a+4(a-10)=a+20

We move all terms to the left:

3a+4(a-10)-(a+20)=0

We multiply parentheses

3a+4a-(a+20)-40=0

We get rid of parentheses

3a+4a-a-20-40=0

We add all the numbers together, and all the variables

6a-60=0

We move all terms containing a to the left, all other terms to the right

6a=60

a=60/6

a=10

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