3a+4(a-2)=12-(8-3a)

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Solution for 3a+4(a-2)=12-(8-3a) equation: 



3a+4(a-2)=12-(8-3a)

We move all terms to the left:

3a+4(a-2)-(12-(8-3a))=0

We add all the numbers together, and all the variables

3a+4(a-2)-(12-(-3a+8))=0

We multiply parentheses

3a+4a-(12-(-3a+8))-8=0



We calculate terms in parentheses: -(12-(-3a+8)), so:

12-(-3a+8)

determiningTheFunctionDomain
-(-3a+8)+12

We get rid of parentheses

3a-8+12

We add all the numbers together, and all the variables

3a+4

Back to the equation:

-(3a+4)



We add all the numbers together, and all the variables

7a-(3a+4)-8=0

We get rid of parentheses

7a-3a-4-8=0

We add all the numbers together, and all the variables

4a-12=0

We move all terms containing a to the left, all other terms to the right

4a=12

a=12/4

a=3

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