3a+4=2(a-4)+13

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Solution for 3a+4=2(a-4)+13 equation: 



3a+4=2(a-4)+13

We move all terms to the left:

3a+4-(2(a-4)+13)=0



We calculate terms in parentheses: -(2(a-4)+13), so:

2(a-4)+13

We multiply parentheses

2a-8+13

We add all the numbers together, and all the variables

2a+5

Back to the equation:

-(2a+5)



We get rid of parentheses

3a-2a-5+4=0

We add all the numbers together, and all the variables

a-1=0

We move all terms containing a to the left, all other terms to the right

a=1

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