3a+c/b=3(d-1)c

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Solution for 3a+c/b=3(d-1)c equation: 


x in (-oo:+oo)

3*a+c/b = 3*c*(d-1) // - 3*c*(d-1)

3*a-(3*c*(d-1))+c/b = 0

3*a-3*c*(d-1)+c/b = 0

(-3*b*c*(d-1))/b+(3*a*b)/b+c/b = 0

3*a*b-3*b*c*(d-1)+c = 0

3*b*c+3*a*b+c-3*b*c*d = 0

(3*b*c+3*a*b+c-3*b*c*d)/b = 0

(3*b*c+3*a*b+c-3*b*c*d)/b = 0 // * b

3*b*c+3*a*b+c-3*b*c*d = 0

x belongs to the empty set

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