3a-(4-4a)+5(a-3)=5

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Solution for 3a-(4-4a)+5(a-3)=5 equation: 



3a-(4-4a)+5(a-3)=5

We move all terms to the left:

3a-(4-4a)+5(a-3)-(5)=0

We add all the numbers together, and all the variables

3a-(-4a+4)+5(a-3)-5=0

We multiply parentheses

3a-(-4a+4)+5a-15-5=0

We get rid of parentheses

3a+4a+5a-4-15-5=0

We add all the numbers together, and all the variables

12a-24=0

We move all terms containing a to the left, all other terms to the right

12a=24

a=24/12

a=2

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