3a-1/a+1=4

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Solution for 3a-1/a+1=4 equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

3*a-(1/a)+1 = 4 // - 4

3*a-(1/a)-4+1 = 0

3*a-a^-1-4+1 = 0

3*a^1-1*a^-1-3*a^0 = 0

(3*a^2-3*a^1-1*a^0)/(a^1) = 0 // * a^2

a^1*(3*a^2-3*a^1-1*a^0) = 0

a^1

3*a^2-3*a-1 = 0

3*a^2-3*a-1 = 0

DELTA = (-3)^2-(-1*3*4)

DELTA = 21

DELTA > 0

a = (21^(1/2)+3)/(2*3) or a = (3-21^(1/2))/(2*3)

a = (21^(1/2)+3)/6 or a = (3-21^(1/2))/6

a in { (3-21^(1/2))/6, (21^(1/2)+3)/6} 

a in { (3-21^(1/2))/6, (21^(1/2)+3)/6 }

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