3a-10=5(a+1)+16a+4

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Solution for 3a-10=5(a+1)+16a+4 equation: 



3a-10=5(a+1)+16a+4

We move all terms to the left:

3a-10-(5(a+1)+16a+4)=0



We calculate terms in parentheses: -(5(a+1)+16a+4), so:

5(a+1)+16a+4

We add all the numbers together, and all the variables

16a+5(a+1)+4

We multiply parentheses

16a+5a+5+4

We add all the numbers together, and all the variables

21a+9

Back to the equation:

-(21a+9)



We get rid of parentheses

3a-21a-9-10=0

We add all the numbers together, and all the variables

-18a-19=0

We move all terms containing a to the left, all other terms to the right

-18a=19

a=19/-18

a=-1+1/18

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