3a-11+5(a-4)=7-3(a+1)

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Solution for 3a-11+5(a-4)=7-3(a+1) equation:



3a-11+5(a-4)=7-3(a+1)
We move all terms to the left:
3a-11+5(a-4)-(7-3(a+1))=0
We multiply parentheses
3a+5a-(7-3(a+1))-20-11=0
We calculate terms in parentheses: -(7-3(a+1)), so:
7-3(a+1)
determiningTheFunctionDomain -3(a+1)+7
We multiply parentheses
-3a-3+7
We add all the numbers together, and all the variables
-3a+4
Back to the equation:
-(-3a+4)
We add all the numbers together, and all the variables
8a-(-3a+4)-31=0
We get rid of parentheses
8a+3a-4-31=0
We add all the numbers together, and all the variables
11a-35=0
We move all terms containing a to the left, all other terms to the right
11a=35
a=35/11
a=3+2/11

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