3a-18=4(-3-3/4a

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Solution for 3a-18=4(-3-3/4a equation: 



3a-18=4(-3-3/4a

We move all terms to the left:

3a-18-(4(-3-3/4a)=0



Domain of the equation: 4a)-18!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

3a-(4(-3/4a-3)-18=0

We multiply all the terms by the denominator


3a*4a-3)-18-(4(-3=0

We add all the numbers together, and all the variables

3a*4a=0

Wy multiply elements

12a^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{24}=0$

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