3a-2(2a-5)=2(a+3)-2

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Solution for 3a-2(2a-5)=2(a+3)-2 equation: 



3a-2(2a-5)=2(a+3)-2

We move all terms to the left:

3a-2(2a-5)-(2(a+3)-2)=0

We multiply parentheses

3a-4a-(2(a+3)-2)+10=0



We calculate terms in parentheses: -(2(a+3)-2), so:

2(a+3)-2

We multiply parentheses

2a+6-2

We add all the numbers together, and all the variables

2a+4

Back to the equation:

-(2a+4)



We add all the numbers together, and all the variables

-1a-(2a+4)+10=0

We get rid of parentheses

-1a-2a-4+10=0

We add all the numbers together, and all the variables

-3a+6=0

We move all terms containing a to the left, all other terms to the right

-3a=-6

a=-6/-3

a=+2

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