3a-2(2a-5)=2(a+3)-2

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Solution for 3a-2(2a-5)=2(a+3)-2 equation:



3a-2(2a-5)=2(a+3)-2
We move all terms to the left:
3a-2(2a-5)-(2(a+3)-2)=0
We multiply parentheses
3a-4a-(2(a+3)-2)+10=0
We calculate terms in parentheses: -(2(a+3)-2), so:
2(a+3)-2
We multiply parentheses
2a+6-2
We add all the numbers together, and all the variables
2a+4
Back to the equation:
-(2a+4)
We add all the numbers together, and all the variables
-1a-(2a+4)+10=0
We get rid of parentheses
-1a-2a-4+10=0
We add all the numbers together, and all the variables
-3a+6=0
We move all terms containing a to the left, all other terms to the right
-3a=-6
a=-6/-3
a=+2

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