3a-2+5a=-3-(-7)+12a

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Solution for 3a-2+5a=-3-(-7)+12a equation: 



3a-2+5a=-3-(-7)+12a

We move all terms to the left:

3a-2+5a-(-3-(-7)+12a)=0

We add all the numbers together, and all the variables

8a-(-3-(-7)+12a)-2=0



We calculate terms in parentheses: -(-3-(-7)+12a), so:

-3-(-7)+12a

determiningTheFunctionDomain
12a-3-(-7)

We add all the numbers together, and all the variables

12a+4

Back to the equation:

-(12a+4)



We get rid of parentheses

8a-12a-4-2=0

We add all the numbers together, and all the variables

-4a-6=0

We move all terms containing a to the left, all other terms to the right

-4a=6

a=6/-4

a=-1+1/2

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