3a-4(a-5)=1

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Solution for 3a-4(a-5)=1 equation: 



3a-4(a-5)=1

We move all terms to the left:

3a-4(a-5)-(1)=0

We multiply parentheses

3a-4a+20-1=0

We add all the numbers together, and all the variables

-1a+19=0

We move all terms containing a to the left, all other terms to the right

-a=-19

a=-19/-1

a=+19

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