3a-4=4(a+1)+10a+6

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Solution for 3a-4=4(a+1)+10a+6 equation: 



3a-4=4(a+1)+10a+6

We move all terms to the left:

3a-4-(4(a+1)+10a+6)=0



We calculate terms in parentheses: -(4(a+1)+10a+6), so:

4(a+1)+10a+6

We add all the numbers together, and all the variables

10a+4(a+1)+6

We multiply parentheses

10a+4a+4+6

We add all the numbers together, and all the variables

14a+10

Back to the equation:

-(14a+10)



We get rid of parentheses

3a-14a-10-4=0

We add all the numbers together, and all the variables

-11a-14=0

We move all terms containing a to the left, all other terms to the right

-11a=14

a=14/-11

a=-1+3/11

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