3a-5(3=2a)+10

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Solution for 3a-5(3=2a)+10 equation: 



3a-5(3=2a)+10

We move all terms to the left:

3a-5(3-(2a)+10)=0

We add all the numbers together, and all the variables

3a-5(-2a+13)=0

We multiply parentheses

3a+10a-65=0

We add all the numbers together, and all the variables

13a-65=0

We move all terms containing a to the left, all other terms to the right

13a=65

a=65/13

a=5

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