3a-5(7a+1)=3a-40

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Solution for 3a-5(7a+1)=3a-40 equation: 



3a-5(7a+1)=3a-40

We move all terms to the left:

3a-5(7a+1)-(3a-40)=0

We multiply parentheses

3a-35a-(3a-40)-5=0

We get rid of parentheses

3a-35a-3a+40-5=0

We add all the numbers together, and all the variables

-35a+35=0

We move all terms containing a to the left, all other terms to the right

-35a=-35

a=-35/-35

a=1

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