3a-5/4-4a=3-(a-3)/2

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Solution for 3a-5/4-4a=3-(a-3)/2 equation: 



3a-5/4-4a=3-(a-3)/2

We move all terms to the left:

3a-5/4-4a-(3-(a-3)/2)=0

We add all the numbers together, and all the variables

-1a-(3-(a-3)/2)-5/4=0

We calculate fractions


-1a+(-(3-(a-3)*4)/()+()/()=0



We calculate terms in parentheses: +(-(3-(a-3)*4)/()+()/(), so:

-(3-(a-3)*4)/()+()/(

We add all the numbers together, and all the variables

-(3-(a-3)*4)/()+1

We multiply all the terms by the denominator


-(3-(a-3)*4)+1*()



We calculate terms in parentheses: -(3-(a-3)*4), so:

3-(a-3)*4

determiningTheFunctionDomain
-(a-3)*4+3

We multiply parentheses

-4a+12+3

We add all the numbers together, and all the variables

-4a+15

Back to the equation:

-(-4a+15)



We add all the numbers together, and all the variables

-(-4a+15)

We get rid of parentheses

4a-15

Back to the equation:

+(4a-15)



We get rid of parentheses

-1a+4a-15=0

We add all the numbers together, and all the variables

3a-15=0

We move all terms containing a to the left, all other terms to the right

3a=15

a=15/3

a=5

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