3a-6+a-7=11+3(a-2)-7

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Solution for 3a-6+a-7=11+3(a-2)-7 equation: 



3a-6+a-7=11+3(a-2)-7

We move all terms to the left:

3a-6+a-7-(11+3(a-2)-7)=0

We add all the numbers together, and all the variables

4a-(11+3(a-2)-7)-13=0



We calculate terms in parentheses: -(11+3(a-2)-7), so:

11+3(a-2)-7

determiningTheFunctionDomain
3(a-2)+11-7

We add all the numbers together, and all the variables

3(a-2)+4

We multiply parentheses

3a-6+4

We add all the numbers together, and all the variables

3a-2

Back to the equation:

-(3a-2)



We get rid of parentheses

4a-3a+2-13=0

We add all the numbers together, and all the variables

a-11=0

We move all terms containing a to the left, all other terms to the right

a=11

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