3a-7(4-a)=10a-28

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Solution for 3a-7(4-a)=10a-28 equation: 



3a-7(4-a)=10a-28

We move all terms to the left:

3a-7(4-a)-(10a-28)=0

We add all the numbers together, and all the variables

3a-7(-1a+4)-(10a-28)=0

We multiply parentheses

3a+7a-(10a-28)-28=0

We get rid of parentheses

3a+7a-10a+28-28=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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