3a-7(4-a)=10a-28

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Solution for 3a-7(4-a)=10a-28 equation:



3a-7(4-a)=10a-28
We move all terms to the left:
3a-7(4-a)-(10a-28)=0
We add all the numbers together, and all the variables
3a-7(-1a+4)-(10a-28)=0
We multiply parentheses
3a+7a-(10a-28)-28=0
We get rid of parentheses
3a+7a-10a+28-28=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0

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