3a-9=4(a+1)+14a+3

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Solution for 3a-9=4(a+1)+14a+3 equation: 



3a-9=4(a+1)+14a+3

We move all terms to the left:

3a-9-(4(a+1)+14a+3)=0



We calculate terms in parentheses: -(4(a+1)+14a+3), so:

4(a+1)+14a+3

We add all the numbers together, and all the variables

14a+4(a+1)+3

We multiply parentheses

14a+4a+4+3

We add all the numbers together, and all the variables

18a+7

Back to the equation:

-(18a+7)



We get rid of parentheses

3a-18a-7-9=0

We add all the numbers together, and all the variables

-15a-16=0

We move all terms containing a to the left, all other terms to the right

-15a=16

a=16/-15

a=-1+1/15

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