3a-9=6(a+1)+12a+2

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Solution for 3a-9=6(a+1)+12a+2 equation: 



3a-9=6(a+1)+12a+2

We move all terms to the left:

3a-9-(6(a+1)+12a+2)=0



We calculate terms in parentheses: -(6(a+1)+12a+2), so:

6(a+1)+12a+2

We add all the numbers together, and all the variables

12a+6(a+1)+2

We multiply parentheses

12a+6a+6+2

We add all the numbers together, and all the variables

18a+8

Back to the equation:

-(18a+8)



We get rid of parentheses

3a-18a-8-9=0

We add all the numbers together, and all the variables

-15a-17=0

We move all terms containing a to the left, all other terms to the right

-15a=17

a=17/-15

a=-1+2/15

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