3a/5a2;=2

Solution for 3a/5a2;=2 equation:

3a/5a^2=2

We move all terms to the left:

3a/5a^2-(2)=0


Domain of the equation: 5a^2!=0

a^2!=0/5

a^2!=√0

a!=0

a∈R


We multiply all the terms by the denominator


3a-2*5a^2=0

Wy multiply elements

-10a^2+3a=0

a = -10; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-10)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-10}=\frac{-6}{-20}
=3/10
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-10}=\frac{0}{-20}
=0
$