3a2+30a+60=-3

Solution for 3a2+30a+60=-3 equation:

3a^2+30a+60=-3

We move all terms to the left:

3a^2+30a+60-(-3)=0

We add all the numbers together, and all the variables

3a^2+30a+63=0

a = 3; b = 30; c = +63;
Δ = b2-4ac
Δ = 302-4·3·63
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-12}{2*3}=\frac{-42}{6}
=-7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+12}{2*3}=\frac{-18}{6}
=-3
$