3a2+9a-54=0

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Solution for 3a2+9a-54=0 equation:



3a^2+9a-54=0
a = 3; b = 9; c = -54;
Δ = b2-4ac
Δ = 92-4·3·(-54)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*3}=\frac{-36}{6} =-6 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*3}=\frac{18}{6} =3 $

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